c语言参考答案(全)

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c语言参考答案(全)

习题11-1填空题1. 函数2. 主函数main(),主函数main()3. 主函数main()4. 函数首部,函数体5. {,}6. /*,*/7. 顺序结构,选择结构,循环结构8. .c,.obj,.exe1-2思考题1. 结构化程序设计是指:为使程序具有一个合理的结构以保证程序正确性而规定的一套如何进行程序设计的原则。顺序结构,选择结构,循环结构2. 算法是对具体问题求解步骤的一种描述。计算机算法的表达工具通常采用以下几种方法:(1)用自然语言表示算(2)用流程图表示算法(3)用伪代码表示算法(4)用程序设计语言表示算法3. 语言简洁、紧凑,使用方便、灵活;支持结构化程序设计;运算符丰富;数据类型丰富;较强的编译预处理功能;C语言的可移植性好;C语言本身既有一般高级语言的优点,又有低级(汇编)语言的特点;语法限制不太严格,程序设计自由度大。4.略5.略1-3编程题1.main(){floata=3,b=4,c=5,s,area;s=(a+b+c)/2;area=sqrt(s*(s-a)*(s-b)*(s-c));printf(“area=%f”,area);}2.main(){printf(“******************************”);printf(“*helloworld*”);printf(“******************************”);n}习题22-1单选题1~5DBDCA6~10DCABA11~14BCAA2-2思考题1.2.000002.1,0.53.9,24.65.100,d6.(1)20(2)0(3)607.(1)10,6,4(2)6,9,15(3)3,60,838.559.70习题33-1单选题1-5 BBDAB6-10 DDBDC11-15 AADCA16-20 CBACC21-25 ABDBB3-2填空题1. 32. 02613. 0x104. 05.2,1 互换a,b的值6. 6.67. –038. 79. 5.0,4,c=310. i=10,j=2011. (1)65(2)65,An(3)56.123400,123.456001(4)3.141600(5)8765.432(6)5.86400e+02(7)3.14160e+00(8)3.1416(9)8765(10)3.1416,8765.4312. a=2b=5x=8.8y=76.34c1=65c2=973-3编程题1.main(){intx,y;scanf(“%d%d”,&x,&y);printf(“xyn”);printf(“%4d%4dn”,x,y);printf(“%4o%4on”,x,y);printf(“%4x%4xn”,x,y);}2.main(){floata,b,h,s;scanf(“%f%f%f”,&a,&b,&h);s=(a+b)*h/2;printf(“%8.1fn”,s);}3.main(){charc;scanf(“%c”,&c);printf(“%c,%c,%cn”,c-1,c,c+1);}4.main(){inta,a1,a2,a3;scanf(“%d”,&a);a1=a%10;a=a/10;a2=a%10;a=a/10;na3=a%10;printf(“%d%d%dn”,a1,a2,a3);}5.main(){doublea,b,c,ave;scanf(“%lf%lf%lf”,&a,&b,&c);ave=(a+b+c)/3;printf(“%8.2fn”,ave);}6.main(){inta,b,c,t;scanf(“%d%d%d”,&a,&b,&c);t=a;a=c;c=b;b=t;printf(“a=%d,b=%d,c=%dn”,a,b,c);}习题44-1单选题1~5BADAC6~10DDACD11~15BBBAB4-2填空题1.12.if(x>0)y=1elseif(x==0)y=0elsey=-13.(1)a>0||b>0(2)x>0&&x<=10(3)a==1.5&&b==1.5&&c==1.5(4)pb?a:b)>c?max:c6.-47.18.5,0,39.85belongstoB10.(1)(a==0)(2)(b==0)(3)(disc<0)n4-3编程题1.#include“math.h”main(){floata,b,c,s,area;scanf(“%f,%f,%f”,&a,&b,&c);if(a+b>c&&a+c>b&&b+c>a){s=(a+b+c)/2;area=sqrt(s*(s-a)*(s-b)*(s-c));printf(“%f”,area);}}2.main(){intx,y;scanf(“%d,%d”,&x,&y);if(x*x+y*y>1000)printf(“%dn”,(x*x+y*y)/100);elseprintf(“%dn”,x+y);}3.main(){intx,scanf(“%d”,&x);if(x%3==0&&x%5==0&&x%7==0)printf(“yesn”);elseprintf(“non”);}4.#include“math.h”main(){floatx,y;scanf(“%f”,&x);if(x<-2)y=x*x-sin(x);elseif(x<=2)y=pow(2,x)+1;elsey=sqrt(x*x+x+1);printf(“%fn”,y);}5.main()n{longa,b,c,d,e,x;scanf("%ld",&x);a=x/10000;/*分解出万位*/b=x%10000/1000;/*分解出千位*/c=x%1000/100;/*分解出百位*/d=x%100/10;/*分解出十位*/e=x%10;/*分解出个位*/if(a!=0)printf("thereare5,%ld%ld%ld%ld%ldn",e,d,c,b,a);elseif(b!=0)printf("thereare4,%ld%ld%ld%ldn",e,d,c,b);  elseif(c!=0)printf("thereare3,%ld%ld%ldn",e,d,c);    elseif(d!=0)printf("thereare2,%ld%ldn",e,d);      elseif(e!=0)printf("thereare1,%ldn",e);}6.1.程序分析:main(){longge,shi,qian,wan,x;scanf("%ld",&x);wan=x/10000;qian=x%10000/1000;shi=x%100/10;ge=x%10;if(ge==wan&&shi==qian)/*个位等于万位并且十位等于千位*/ printf("thisnumberisahuiwenn");else printf("thisnumberisnotahuiwenn");}7.main(){floatp,w,s,d,f;scanf(“%f,%,%f”,p,s,w);if(s>3000)d=0.15elseif(s>=2000)d=0.1;elseif(s>=1000)d=0.08;elseif(s>=500)d=0.05;elseif(s>=250)d=0.02;elsed=0f=p*w*s*(1-d);printf(“%f”,f);}n习题55-1单选题1~5CDACB6~10DCAAB11~16DBDBCB5-2填空题1.202.k=5,s=43.3334.HowAreYou5.2#18#6.(1)i<10(2)j%3!=07.(1)flag*(float)k/(k+1)(2)flag=-flag8.(1)s=0,t=1;(2)t=t*x/i*pow(-1,i+1);(3)printf(“%f”,s);9.(1)max=x(2)x!=-1(3)scanf("%d",&x)10.(1)n=1(2)s5-3编程题1.(1)main(){inti;lonts=0;for(i=1;i<=100;i++)s+=i*i;printf(“%ld”,s);}(2)main(){inti;lontp=1,s=0;for(i=1;i<=10;i++){p=p*i;s+=p;}printf(“%ld”,s);}(3)main(){inti=1;lontp=1;floats=0;do{s+=1.0/p;p*=++i;}while(1.0/p>1e-6)nprintf(“%f”,s);}(4)main(){inti=1,flag=1,pi=0;do{s+=flag*1.0/(2*i-1);i++;}while(1.0/(2*i-1)>1e-6);printf(”%f”,s);}2.main(){intm,n,t,a,b;scanf(“%d,%d” ,&m,&n) ;if(m0 ;y--)s*=x ;printf(”%d,%d,%dn ”,s%10,s/10%10,s/100%10);}4.main(){inti=1,k=2,sum=0;do{sum+=k;k=k*2;i++;}while(sum<=100);printf(”total=%fn”,0.4*sum/(i-1));}5.main(){intx,y,z;for(x=1 ;x<20 ;x++)for(y=1 ;y<33 ;y++){z=100-x-y ;nif(z>=0&&(5*x+3*y+z/3)-100<1e-5)printf(”x=%d,y=%d,z=%dn”,x,y,z) ;}}6.main(){intj,k ;for(j=1 ;j<=4 ;j++){for(k=1;k<=4-j;k++;)printf(””);for(k=1 ;k<=2*j-1 ;k++)printf(”*”) ;printf(”n”) ;}for(j=3;j>=1;j--){for(k=1;k<=4-j;k++;)printf(””);for(k=1;k<=2*j-1;k++)printf(”*”);printf(”n”);}}7.分析:其实此问题的解法非常简单。从数学上来说,可以用穷举法。比如让x从2开始,判断表达式“(x%3==2&&x%5==3&&x%7==2)”是否成立,若不成立,让x自增1,直到某个x满足条件了,则这个x即为所求。程序如下:#includemain(){intx=2;while(!(x%3==2&&x%5==3&&x%7==2)){x++;}printf("x=%dn",x);}程序运行结果:    x=238分析:定义一个字符变量c和一个整型变量n,c用于接受从键盘输入的非回车行字符,n用于统计从键盘输入的非回车符字符的个数,也就是说,以(c=getchar())!='n'为循环条件,反复进行“n++;”的运算。程序代码如下:#includevoidmain(){nintn=0;charc;printf("inputastring:n");while((c=getchar())!='n')n++;printf("%d",n);}9.例如:153是一个“水仙花数”,因为153=1的三次方+5的三次方+3的三次方。程序分析:利用for循环控制100-999个数,每个数分解出个位,十位,百位。main(){inti,j,k,n;printf("'waterflower'numberis:"); for(n=100;n<1000;n++) {  i=n/100;/*分解出百位*/  j=n/10%10;/*分解出十位*/  k=n%10;/*分解出个位*/  if(i*100+j*10+k==i*i*i+j*j*j+k*k*k)   {   printf("%-5d",n);   } }printf("n");}10.main(){intx,y,z;for(x=1 ;x<17 ;x++)for(y=1 ;y<25 ;y++){z=30-x-y ;if(z>0&&3*x+2*y+z==50)printf("man=%d,woman=%d,child=%dn”,x,y,z);}}习题66-1单选题1-5 CBBAD6-10 DBAAC11-15 CCDDC16-20 BBABCn6-2填空题1. 1202. x3. 3,2,2,34./I5. 8,176. 97. 1.0/(i*i)8. fun-in:30,20,10fun-end:1015,35,105010,20,309. 01234510.936366-3编程题1.voidzhuan(){charch;while((ch=getchar())!=’n’){if(ch>=’a’&&ch<=’z’)ch=ch-32;putchar(ch);}}2.floatexpp(intn){intk,fac=1;floatsum=0;for(k=1;k<=n;k++){fac*=k;sum+=1.0/fac;}return(sum);}3.intxy3(intx,inty){intk,num=1;for(k=1;k<=y;k++)num*=x;num=num%1000;returnnum;}n4.voidfactors(intn){intk;printf(“%ditsfactorsare:”,n);for(k=1;ka[j]3.(1)r+b[k](2)*x8-3编程题1.#defineN10main(){inta[N]={1,2,3,4,5,6,7,8,9,0},osum=0,qsum=0,j;for(j=0;j<10;j++)if(j%2)qsum+=a[j];elseosum+=a[j];printf(“osum=%d,qsum=%dn”,osum,qsum);}2.#defineN10main(){inta[N]={10,20,30,40,50,60,70,80,90},j,k,x;scanf(“%d”,&x);for(j=0;jj;k--)a[k]=a[k-1];a[j]=x;for(j=0;j=’a’&&c[j]<=’z’)?c[j]-32:c[j];puts(c);}7.#include“string.h”main(){charc1[10],c2[10],j;gets(c1);gets(c2);for(j=0;(c1[j]==c2[j])&&c1[j]&&c2[j];j++);printf(“%dn”,c1[j]-c2[j]);}8.#include”string.h”#defineM3n#defineN80main(){chara[M][N],j,k,n[5]={0};for(j=0;j=’A’&&a[j][k]<=’Z’)n[1]++;elseif(a[j][k]>=’a’&&a[j][k]<=’z’)n[2]++;elseif(a[j][k]>=’0’&&a[j][k]<=’9’)n[3]++;elseif(a[j][k]=’’)n[4]++;elsen[5]++;for(j=0;j<5;j++)printf(“%4d”,n[j]);}习题99-1单选题1~5DDBAC6~10BADCB11~15ADCDA16~20CCABD9-2填空题1.(1)2,1(2)10#30#5#(3)FOUR,O(4)602.(1)49(2)AC(3)2(4)2(5)3,12,39(6)75319(7)15012345678910111213140522713(8)12,10,9,6,5,4,3,2,1(9)1,1,11,13,3,33,3(10)1000101010001000101010001(11)3.(1)*x(2)t4.(1)''或0(2)n++或n+=1或n=n+15.ABCDCDn6.0247.voidfun(doubleb[][22])或voidfun(doubleb[0][22])或voidfun(double(*b)[22])8.(1)f(x+y)/g(y-x)或(*f)(x+y)/g(y-x)或f(x+y)/(*g)(y-x)或(*f)(x+y)/(*g)(y-x)(2)cos,sin,a,b9-3编程题1.按以下要求编写一个程序。定义三个变量用于存放输入的三个整数;另定义三个指向整型变量的指针变量,并利用它们实现将输入的三个整数按由小到大的顺序输出。main(){intn1,n2,n3;int*pointer1,*pointer2,*pointer3;printf("pleaseinput3number:n1,n2,n3:");scanf("%d,%d,%d",&n1,&n2,&n3);pointer1=&n1;pointer2=&n2;pointer3=&n3;if(n1>n2)swap(pointer1,pointer2);if(n1>n3)swap(pointer1,pointer3);if(n2>n3)swap(pointer2,pointer3);printf("thesortednumbersare:%d,%d,%dn",n1,n2,n3);}swap(p1,p2)int*p1,*p2;{intp;p=*p1;*p1=*p2;*p2=p;}2.编写函数,得到两个整数相除的商和余数。要求通过指针在函数间传递商和余数这两个数据。main(){inta,b,d ;floatc;voidfun(inta,intb,float*c,int*d)scanf(“%d,%d “,&a,&b);fun(a,b,&c,&d);printf(“%f%d”,c,d);}voidfun(inta,intb,float*c,int*d){if(b){*c=(float)a/b;*d=a%b;}}3.输入10个整数,将其中最小的数与第一个数对换,把最大的数与最后一个数对换。编写三个函数:①输入10个数;②进行处理;③输出10个数。nmain(){voidinput(int*);voidoutput(int*);voidchuli(int*);inta[10];input(a);chuli(a);output(a);}voidinput(int*a){intj;for(j=0;j<10;j++)scanf(”%d”,a+j);}voidchuli(int*a){intj,minl=0,maxl=0;for(j=0;j<10;j++){if(a[maxl]<*(a+j))maxl=j;if(a[minl]>*(a+j))minl=j;}j=a[0];a[0]=a[minl];a[minl]=j;j=a[9];a[9]=a[maxl];a[maxl]=j;}voidoutput(int*a){intj;for(j=0;j<10;j++)printf(”%d”,*(a+i));}4.有n个整数,使前面各数顺序向后移m个位置,最后m个数变成最前面m个数,写一函数实现以上功能,在主函数中输入n个整数和输出调整后的n个数。main(){intnumber[20],n,m,i;printf("thetotalnumbersis:");scanf("%d",&n);printf("backm:");scanf("%d",&m);for(i=0;iarray;p--) *p=*(p-1); *array=array_end; m--; if(m>0)move(array,n,m);}5.有n个小孩按顺序号排成一圈。从第1个小孩开始作1至3报数,凡是报数为3的小孩退出圈子,求出最后出圈子的那个小孩是原来第几号的那位。#defineN10#defineM3main(){inta[N],j;voidchuli(int*);for(j=0;j=j;k--)a[k+1]=a[k];a[j]=t;}}5.#definenmax50main(){inti,k,m,n,num[nmax],*p;printf("pleaseinputthetotalofnumbers:");scanf("%d",&n);p=num;for(i=0;in)printf(“error”);elsecopysubstr(c1,c2,m);puts(c1);puts(c2);}voidcopysubstr(char*c1,char*c2,intm){intk;c1=c1+m;while(*(c1))*(c2++)=*(c1++);}9.请编写一个程序,运行时输出命令行参数的个数及参数名。main(intargc,char*argv[]){intk;printf(“argc=%d”,argc);for(k=1;k0)t=j;c=*(str1+t);*(str1+t)=*(str1+k) ;*(str1+k)=c ;}}习题1010-1单选题1-5 CDBBC6-10 BBBBA11-15 DCCBD16-20 CBABC21-22 CB10-2填空题1. 所有结构体成员所占存储空间的总和2. 与占用存储空间最大的那个成员相等3. (1)结构体 (2)3 (3)sa.a (4)7 (5)psa=&sa4. 805. structnode6. double*7. 08. malloc(11)9. structSTRU10. structSTRUn10-3编程题1.structstudent{longnum;charname[20];charsex;floatscore;};main(){structstudents[20],temp;intj,k,man=0,woman=0;floatsumman=0,sumwoman=0,aveman,avewoman;for(k=0;k<20;k++){scanf("%ld%s%c%f",&s[k].num,s[k].name,&s[k].sex,&s[k].score);if(s[k].sex==’m’){summan+=s[k].score;man++;}else{sumwoman+=s[k].score;woman++;}}aveman=summan/man;avewoman=sumwoman/woman;printf("%dt%ft%dt%fn",man,aveman,woman,avewoman);for(k=0;k<19;k++)for(j=0;j<20-k;j++)if(s[j].scorenext!=NULL)p=p.next;elsereturn(head);while(p->next!=NULL){q->next=r;r=q;q=p;p=p->next;/*指针移向下一个结点*/}q->next=r;p->next=q;head->next=NULL;head=p;return(head);}习题1111-1单选题1-4 BADD11-2填空题1. 3d3d3302. (1)28 (2)20 (3)0 (4)-93. (1)251 (2)42 (3)209 (4)–295 (5)848习题1212-1单选题1-5 BCDCA 6-8 ADA12-2填空题1. rewind(文件指针)2. "d1.dat","rb"3. stdin4. 字符串常量字符数组名5. 文本文件 二进制文件n6. 从fp所指向的文件中读6个4字节的数据,存储到起始地址为st的实型数组中(即st[0]~st[5]中)。7. (1)"w" (2)str[i]-32 (3)"r"8. fopen9. Hell10. (1)"r" (2)fgetc(fp) (3)time++实验篇实验1顺序结构程序设计(1)略(2)略(3)略(4)#include"stdio.h"main(){printf("n");printf("4+---+---+---+n");printf("||||n");printf("3+---+---+---+n");printf("||||n");printf("2+---+---+---+n");printf("||||n");printf("1+---+---+---+n");printf("1234n");}(5)略实验2选择结构程序设计(1)略(2)略(3)#include“stdio.h”main(){unsignedintx;printf("Pleaseinputanunsigneddata:");scanf("%d",&x);nif(x%2==0)printf("thedata%disaneven!",x);elseprintf("thedata%disanodd!",x);}(1)#include"stdio.h"main(){floata,b;printf("Pleaseinputthedataaandb:n");scanf("%f%f",&a,&b);if(a>10.0)a=a-10.0;else{a=a+10.0;if(b>a);elseb=a-b;}printf("a=%f,b=%fn",a,b);}(5)#include"stdio.h"main(){floatx,y;printf("Pleaseinputthedatax:n");scanf("%f",&x);if(x<0&&x!=-3)y=x*x+x-6;elseif(x>=0&&x<10&&x!=2&&x!=3)y=x*x-5*x+6;elsey=x*x-x-1;printf("x=%f,f(x)=%fn",x,y);}(6)#include"stdio.h"main(){intt,a,b,c,d;printf("Pleaseenterthedata:a,b,c,d:n");nscanf("%d%d%d%d",&a,&b,&c,&d);if(a40)printf("r=%f,area=%fn",r,area);r=r+1;area=3.1415926*r*r;}}(4)#include"stdio.h"main(){intx,i=0;scanf("%d",&x);while(x>=0){if(x<=100)i++;scanf("%d",&x);n}printf("thenumberis:%dn",i);}(5)#include"math.h"main(){doublek=1.0,n=1.0,pi=0,t=1.0;while(fabs(t)>=1e-4){pi=pi+t;n=n+2.0;k=-k;t=k/n;}pi=pi*4;printf("pi=%lfn",pi);}(6)#includemain(){inti,m,n;for(n=1,i=1;i<10;i++){m=2*n+2;n=m;}printf("total=%dn",m);}(7)#include"math.h"#include"stdio.h"#defineM10main(){intn,i,k,sk,flag,s=0;printf("Pleaseinputthedata:n");for(n=1;n<=M;n++){scanf("%d",&k);flag=1;sk=sqrt(k);for(i=2;i<=sk;i++)nif(k%i==0){flag=0;break;}if(flag==1)s=s+k;}printf("sum=%dn",s);}(8)#include"stdio.h"main(){intn,white,red,black,count=0;printf("Pleaseinputthenumberofballtook:");scanf("%d",&n);printf("whiteredblackn");for(white=0;white<=3;white++)for(red=0;red<=3;red++){black=n-white-red;if(black>=0&&black<=6){printf("%6d%6d%6dn",white,red,black);count++;}}printf("Total:%dn",count);}实验4函数(1)略(2)略(3)#include"stdio.h"voidaa(int);main(){intn;printf("Pleaseinputtheinteger:n");scanf("%d",&n);aa(n);n}voidaa(intx){intm,n;m=x%10;n=x/10;if(n>0)aa(n);printf("%d",m);}(4)使用全局变量:#include"stdio.h"intx,y;inthef(){intu=x,v=y,a,b;if(u>v){a=u;u=v;v=a;}while((b=u%v)!=0){u=v;v=b;}return(v);}intled(intx,inty,inth){return(x*y/h);}main(){inth,l;scanf("%d%d",&x,&y);h=hef(x,y);printf("HCF=%dn",h);l=led(x,y,h);nprintf("LCD=%dn",l);}不用全局变量:#include"stdio.h"inthef(intx,inty){inta,b;if(y>x){a=x;x=y;y=a;}while((b=x%y)!=0){x=y;y=b;}return(y);}intled(intx,inty,inth){return(x*y/h);}main(){intx,y,h,l;scanf("%d%d",&x,&y);h=hef(x,y);printf("HCF=%dn",h);l=led(x,y,h);printf("LCD=%dn",l);}(5)#include"stdio.h"voidlsum(intn);voidrsum(intn);voidlsumc(intn);voidrsumc(intn);main(){nlsum(10000);rsum(10000);lsumc(10000);rsumc(10000);}voidlsum(intn){inti,k=1;doublesum=0,t;for(i=1;i<=n;i++){t=1.0*k/i;sum+=t;k=-k;}printf("thelsumis:%lfn",sum);}voidrsum(intn){inti,k=-1;doublesum=0,t;for(i=n;i>=1;i--){t=1.0*k/i;sum+=t;k=-k;}printf("thersumis:%lfn",sum);}voidlsumc(intn){inti;doublesum=0;for(i=1;i<=n-1;i++,i++)sum+=1.0/i;for(i=2;i<=n;i++,i++)sum-=1.0/i;printf("thelsumcis:%lfn",sum);}voidrsumc(intn){inti;doublesum=0;for(i=n;i>=2;i--,i--)nsum-=1.0/i;for(i=n-1;i>=1;i--,i--)sum+=1.0/i;printf("thersumcis:%lfn",sum);}(6)#include"stdio.h"intmonkey(intk){inti,m,n;for(n=1,i=1;i<=10-k;i++){m=2*n+2;n=m;}return(n);}main(){intday;printf("Pleaseinputtheday(1<=day<=10):n");scanf("%d",&day);printf("day:%d,total:%d",day,monkey(day));}(7)#include"stdio.h"voidview1();voidview2();main(){intop;printf("n************************************n");printf("Menusectionn");printf("1.view(@)n");printf("2.view($)n");printf("3.exitn");printf("************************************n");printf("nPleaseinputselection:n");while(1){scanf("%d",&op);if(op==1){view1();printf("nPleaseinputselection:");n}elseif(op==2){view2();printf("nPleaseinputselection:");}elsereturn;}}voidview1(){inti;for(i=1;i<15;i++)putchar('@');return;}voidview2(){inti,j;for(i=1;i<5;i++){for(j=1;ja[i][k])k=j;for(j=0;jx)break;for(j=n;j>i;j--)*(p+j)=*(p+j-1);*(p+i)=x;}实验7结构体和共用体(1)略(2)略(3)#include"stdio.h"structlist{charxh[4];charxm[10];charxb;intnl;structlist*next;};typedefstructlistSLIST;SLIST*creat_list(){SLIST*h,*s,*r;inti;h=(SLIST*)malloc(sizeof(SLIST));r=h;for(i=0;i<3;i++){s=(SLIST*)malloc(sizeof(SLIST));scanf("%s%s%d%c",s->xh,s->xm,&s->nl,&s->xb);r->next=s;r=s;}r->next=NULL;returnh;}voiddele_list(SLIST*p,intage)n{SLIST*q=p->next;while(q)if(q->nl!=age){p=p->next;q=q->next;}else{p->next=q->next;break;}}main(){SLIST*head,*p;intage;head=creat_list();printf("Pleaseinputtheage:n");scanf("%d",&age);dele_list(head,age);p=head->next;while(p!=NULL){printf("%s,%s,%c,%dn",p->xh,p->xm,p->xb,p->nl);p=p->next;}}实验8文件(1)略(2)#include"stdio.h"main(intargc,char*argv[]){FILE*in,*out;if(argc!=3){printf("pleaseenterthefilename");exit(0);}if((in=fopen(argv[1],"r"))==NULL){printf("cannotopeninfilen");exit(0);}if((out=fopen(argv[2],"w"))==NULL){printf("cannotopenoutfilen");nexit(0);}while(!feof(in))fputc(fgetc(in),out);fclose(in);fclose(out);}
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